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problem with valid Qnames

2005-07-25 02:26:05

Hello

I'd like to transform this:

<?xml version="1.0" encoding="UTF-8"?>
<csvFile>
        <line>
                <value>Nom</value>
                <value>Prenom</value>
                <value>Sexe</value>
        </line>
        <line>
                <value>Burke</value>
                <value>Eric</value>
                <value>H</value>
        </line>
        <line>
                <value>Burke</value>
                <value>Jennifer</value>
                <value>F</value>
        </line>
        <line>
                <value>Burke</value>
                <value>Aidan</value>
                <value>H</value>
        </line>
</csvFile>

Into this :

<data>
        <line>
                <nom>Burke</nom>
                <prenom>Eric</nom>
                <sexe>H</nom>
        </line>
        <line>
              <nom>Burke</nom>
                <prenom>Jenifer
                ...
        </line>
...

I'm using this stylesheet :

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

    <xsl:template match="/">
                <data>
                        <xsl:apply-templates select="*"/>
                </data>         
    </xsl:template>
    
        <xsl:template match="line">
                <xsl:if test="not(position()=1)">
                        <line>  
                                <xsl:apply-templates select="value"/>
                        </line>
                </xsl:if>
        </xsl:template>
        
        <xsl:template match="value">
                <xsl:variable name="pos" select="position()"/>
                <xsl:variable name="name"
select="//line[1]/value[$pos]"/>
                <xsl:element name="$name"><xsl:value-of
select="."/></xsl:element>
        </xsl:template>
</xsl:stylesheet>

But I get an error because $name is not a valid Qname

How do I solve this?

Philippe


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