Read about Muenchian grouping at http://www.jenitennison.com/xslt/grouping.
You can use the same idea to test whether a value is unique within the file
(a member of a group of one) by defining the grouping key
<xsl:key name="gk" match="b|bb|bbb" use="."/>
and testing a node
<xsl:template match="b|bb|bbb">
<xsl:if test="not(key('gk', .)[2])">
The value is unique
</xsl:if>
</xsl:template>
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Jonathan Marenus [mailto:jonathanmarenus(_at_)yahoo(_dot_)com]
Sent: 18 July 2005 23:35
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Outputing a node whose value appears only once
What I would like to do now is output a value that
appears only once throughout the XML file. For
example, if I have:
<a>
<b>value1</b>
<bb>value2</bb>
<bbb>value3</bbb>
</a>
<c>
<b>value1</b>
<bb>value2</bb>
<bbb>value4</bbb>
</c>
From the point of view of 'a', I would want to output
"value3" because 'a' contains it but 'c' does not.
This is assuming that the above is the entire file. I
also need to output a sibling of the node which does
not appear more than once (like the value of a/b or
a/bbb). It is also assumed that multiple instances of
the same value will have different parents. This is
shown in the example above.
Thanks for the help.
Jonathan
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