David
Very clever, turned my convoluted 40+ lines into half a dozen.
Thanks
Joe
From: David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Sorting problem
Date: Wed, 31 Aug 2005 12:49:18 +0100
me> No. keys are what you _do_ use in xslt 1 in this case. (in xslt2 you
me> could use xsl:for-each-group)
Or rather you could use keys here, but in this case, i think you just want
to sort don't you?
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0" >
<xsl:output method="xml" indent="yes"/>
<xsl:template match="root">
<root>
<xsl:for-each select="item">
<xsl:sort data-type="number"
select="count(preceding-sibling::item[(_at_)type=current()/@type])"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>
produces
$ saxon item.xml item.xsl
<?xml version="1.0" encoding="utf-8"?>
<root>
<item type="A" subType="1"/>
<item type="B" subType="2"/>
<item type="D" subType="1"/>
<item type="E" subType="2"/>
<item type="A" subType="2"/>
<item type="B" subType="3"/>
<item type="D" subType="2"/>
<item type="E" subType="4"/>
<item type="A" subType="4"/>
<item type="D" subType="3"/>
<item type="D" subType="4"/>
</root>
which appears to be what you wanted.
David
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