I'm using the following:
contains(elem, val)
It's possible that 'elem' can be a sequence of more than one item.
The way I've code around this is to use string-join with an empty
string as one of the arguments:
contains(string-join(for $i in elem return $i, ''), val)
Is there a better way?
1. The expression
for $i in elem return $i
can be rewritten as
elem
So you get
contains(string-join(elem, ''), val)
2. Do you want to match substrings that cross item boundaries, e.g. do you
want contains(('red', 'green'), 'edgr') to be true? If so, I don't think you
can do better than the above. If you don't want this, then apply contains to
each string in the sequence separately:
exists(elem[contains(., val)])
Michael Kay
http://www.saxonica.com/
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