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Re: How to sort attribute?

2005-08-13 02:32:34
Hi John,
  This could be the use-case for the problem you are trying to solve.

XML file -
<root>
  <x a="1" d="2" c="4" />
</root>

XSLT file -
<?xml version="1.0"?> 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">
 
<xsl:output method="xml" indent="yes" /> 
 
<xsl:template match="/root">
   <xsl:apply-templates select="x" />
</xsl:template>
 
<xsl:template match="x">
   <x>
     <xsl:for-each select="@*">
      <xsl:sort select="name()"/>
      <xsl:attribute name="{name()}"><xsl:value-of select="." /></xsl:attribute>
     </xsl:for-each>
   </x>  
</xsl:template>
 
</xsl:stylesheet>

Regards,
Mukul

On 8/13/05, John Li <johnli121(_at_)163(_dot_)com> wrote:
Hi,

When exporting one node and its attribute, I want to sort its attributes
lexicographic. I try it as below but always fail. Anyone could help?

<xsl:for-each select="@*">
   <xsl:sort select="name()"/>
   <xsl:copy/>
</xsl:for-each>

Thanks,
John



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