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Re: AW: xsl:key function help

2005-08-04 00:40:01
Tempore 08:22:25, die 08/04/2005 AD, hinc in 
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com scripsit David Preuss 
<d(_dot_)preuss(_at_)de(_dot_)kddi(_dot_)com>:

That is OK so far because I can understand. Regarding the Muenchian method
which is described on Jenis site I tried the following:

<?xml version='1.0' encoding='UTF-8'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:key name="Categories" match="Tip" use="@Topic" />
<xsl:output method="xml"/>
        
        <xsl:template match="/">                
                <xsl:apply-templates select="Tip[generate-id(.) =
generate-id(key('Categories',@Topic)[1])]"/>
        </xsl:template>

        <xsl:template match="Tip" >
                <xsl:for-each select="key('Categories', @Topic)">
                        <xsl:value-of select="@Subtopic"/>
                </xsl:for-each>
        </xsl:template>

The usage of the 'key()' function and the implementation of the Muenchian 
grouping is 100% correct.
The problem is really much easier:
You do not want <xsl:template match="/">
but instead: <xsl:template match="TipDatabase">

regards,
--
Joris Gillis (http://users.telenet.be/root-jg/me.html)
«Η αλήθεια και το λάδι πάντα βγαίνουν από πάνω»

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