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RE: Ignore Namespace while transformation

2005-09-28 05:10:04
An element name consists of two parts: the namespace name and the local
name. Asking to ignore the namespace is the same as asking to ignore the
local name. You can ignore both by using *. You can ignore the local name by
using prefix:*. In 2.0 you can ignore the namespace using *:local. This
isn't available in 1.0, on the theory that a local-name is meaningless
unless you know what namespace it is in.

Michael Kay
http://www.saxonica.com/ 


-----Original Message-----
From: jaya vardhani [mailto:jayavardhani(_at_)yahoo(_dot_)co(_dot_)in] 
Sent: 28 September 2005 07:32
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Ignore Namespace while transformation

Hi

My XML goes like this:

<?xml version="1.0"?>
<SubmitRequestResponse xmlns="urn:Cserv.CWS">
  <SubmitRequestResult>
    <CAPI xmlns="http://integration.api.com";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
xmlns:xenc="http://www.w3.org/2001/04/xmlenc#";
xsi:schemaLocation="http://integration.api.com
DocumentInquiry.xsd">
      <CHeader Version="2.0">
           ..............
        </CHeader>
    </CAPI>
  </SubmitRequestResult>
</SubmitRequestResponse>

   In my xsl i am not able to match with any element
pattern from the XMl. When i remove the xmlns from
<SubmitRequestResponse> and <CAPI> elements its
working fine. Is there any way that i can transform
the XML without taking these namespaces into
consideration? Please give a solution.

Thanks&Regards,
Jaya M.

 
  


              
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