You can:
In XSLT 1.0 this:
<?xml version="1.0" encoding="UTF-8"?>
<ax:repeat xmlns:ax="uri:axnamespace">
<sometag>
<ax:items element="txt">
<ax:item src="txt1.txt"/>
<ax:item src="txt2.txt"/>
</ax:items>
<ax:items element="img">
<ax:item src="img1.jpg"/>
<ax:item src="img2.jpg"/>
</ax:items>
</sometag>
</ax:repeat>
Processed by this:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:ax="uri:axnamespace"
version="1.0">
<xsl:template match="/">
<xsl:apply-templates select="ax:repeat/*" mode="initial"/>
</xsl:template>
<xsl:template match="*" mode="initial">
<xsl:apply-templates select="*" mode="universal">
<xsl:with-param name="name" select="name()"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="*" mode="universal">
<xsl:param name="name"/>
<xsl:variable name="position" select="position()"/>
<xsl:element name="{$name}">
<xsl:apply-templates select="../*/*[position() =
$position]" mode="parent">
<xsl:with-param name="name" select="@element"/>
</xsl:apply-templates>
</xsl:element>
</xsl:template>
<xsl:template match="*" mode="parent">
<xsl:param name="name"/>
<xsl:param name="parentName"/>
<xsl:element name="{$parentName}">
<xsl:apply-templates select="." mode="child">
<xsl:with-param name="name" select="$name"/>
</xsl:apply-templates>
</xsl:element>
</xsl:template>
<xsl:template match="*" mode="child">
<xsl:param name="name"/>
<xsl:element name="{$name}">
<xsl:copy-of select="@*"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
=
<?xml version="1.0" encoding="utf-8"?>
<sometag>
<txt src="txt1.txt"/>
<txt src="img1.jpg"/>
</sometag>
<sometag>
<img src="txt2.txt"/>
<img src="img2.jpg"/>
</sometag>
This relies on the idea the child count and the parent count being
exactly the same. Theres a way to write so this isn't the case but if
we gave you all the answers you wouldnt have any fun :)
As such, have fun :)
On 9/28/05, Ragulf Pickaxe <ragulf(_dot_)pickaxe(_at_)gmail(_dot_)com> wrote:
The real problem is that I don't want to have to know anything about
<sometag>. That is, I would be free to use (and nest!) whatever
non-proprietary tag inside my <repeat>, without modifing it.
Probably there's no way in XSLT 1.0 (if it is, why creating tunnel in
2.0 ;) , but if you see another solution...
Hi again Paolo,
Why can you not have a general template for the "Sometag" and other
elements that you just want to pass on?
I think that your own solution would be able to provide, if you change
the template that matches "Sometag" to the following:
<xsl:template match="*">
<xsl:param name="index" select="1"/>
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates>
<xsl:with-param name="index" select="$index"/>
</xsl:apply-templates>
<!-- sometag content -->
</xsl:copy>
</xsl:template>
The match="ax:items" is more specific than match="*" and thus has
higher priority.
My solution, I think, you would have to change three templates:
<xsl:template match="ax:repeat">
<xsl:apply-templates/> <!-- instead of <xsl:apply-templates
select="sometag"/>-->
</xsl:template>
<xsl:template match="*"> <!-- Instead of <xsl:template match="sometag" -->
<xsl:copy> <!-- Copy element (shallow copy) -->
<xsl:copy-of select="@*"/> <!-- Copy all attributes -->
<!-- other non-proprietary elements to be processed: -->
<xsl:apply-templates select="*[not(self::ax:items)]"/>
<!-- Propriotary elements to be processed: -->
<xsl:apply-templates select="ax:items[1]" mode="first"/>
</xsl:copy>
</xsl:template>
And remove the <sometag> and </sometag>from the
<xsl:template match="ax:items" mode="first">
..
</
Is this what you need?
Regards,
Ragulf Pickaxe :-)
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