group together child cousins,
Uh, that would just be cousins... I started to write child and change
my mind to cousin... helps if you delete the word you don't wan't,
doesnt it :D
On 9/28/05, M. David Peterson <m(_dot_)david(_dot_)x2x2x(_at_)gmail(_dot_)com>
wrote:
Actually, I misread your desired output... this actually elimates two
lines of code, but increases processing time because of crawling back
up the tree to get the value of the parents @element. But, its not a
huge deal unless you are processing heavy amounts of input where
performance is crucial...
The updated code (still dependent on position... again, you need to
have something that make coding fun... having ALL the answers spoon
fed doesn't help you understand how it works, but having pieces of the
puzzle definitely helps... as such heres piece two of three pieces to
make this completely non dependent on the count of the parent elements
as well as increase performance by a decent chunk... keep in mind,
you're attempting to group together child cousins, in birth order...
grouping almost always points to a particular way of doing things...
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:ax="uri:axnamespace"
version="1.0">
<xsl:template match="/">
<xsl:apply-templates select="ax:repeat/*" mode="initial"/>
</xsl:template>
<xsl:template match="*" mode="initial">
<xsl:apply-templates select="*" mode="universal">
<xsl:with-param name="name" select="name()"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="*" mode="universal">
<xsl:param name="name"/>
<xsl:variable name="position" select="position()"/>
<xsl:element name="{$name}">
<xsl:apply-templates select="../*/*[position() =
$position]" mode="parent"/>
</xsl:element>
</xsl:template>
<xsl:template match="*" mode="parent">
<xsl:param name="name"/>
<xsl:param name="parentName"/>
<xsl:element name="{$parentName}">
<xsl:apply-templates select="." mode="child">
<xsl:with-param name="name" select="$name"/>
</xsl:apply-templates>
</xsl:element>
</xsl:template>
<xsl:template match="*" mode="child">
<xsl:element name="{parent::*/@element}">
<xsl:copy-of select="@*"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
produces:
<?xml version="1.0" encoding="utf-8"?>
<sometag>
<txt src="txt1.txt"/>
<img src="img1.jpg"/>
</sometag>
<sometag>
<txt src="txt2.txt"/>
<img src="img2.jpg"/>
</sometag>
which is what you had in your sample...
Enjoy!
On 9/28/05, M. David Peterson
<m(_dot_)david(_dot_)x2x2x(_at_)gmail(_dot_)com> wrote:
You can:
In XSLT 1.0 this:
<?xml version="1.0" encoding="UTF-8"?>
<ax:repeat xmlns:ax="uri:axnamespace">
<sometag>
<ax:items element="txt">
<ax:item src="txt1.txt"/>
<ax:item src="txt2.txt"/>
</ax:items>
<ax:items element="img">
<ax:item src="img1.jpg"/>
<ax:item src="img2.jpg"/>
</ax:items>
</sometag>
</ax:repeat>
Processed by this:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:ax="uri:axnamespace"
version="1.0">
<xsl:template match="/">
<xsl:apply-templates select="ax:repeat/*" mode="initial"/>
</xsl:template>
<xsl:template match="*" mode="initial">
<xsl:apply-templates select="*" mode="universal">
<xsl:with-param name="name" select="name()"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="*" mode="universal">
<xsl:param name="name"/>
<xsl:variable name="position" select="position()"/>
<xsl:element name="{$name}">
<xsl:apply-templates select="../*/*[position() =
$position]" mode="parent">
<xsl:with-param name="name" select="@element"/>
</xsl:apply-templates>
</xsl:element>
</xsl:template>
<xsl:template match="*" mode="parent">
<xsl:param name="name"/>
<xsl:param name="parentName"/>
<xsl:element name="{$parentName}">
<xsl:apply-templates select="." mode="child">
<xsl:with-param name="name" select="$name"/>
</xsl:apply-templates>
</xsl:element>
</xsl:template>
<xsl:template match="*" mode="child">
<xsl:param name="name"/>
<xsl:element name="{$name}">
<xsl:copy-of select="@*"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
=
<?xml version="1.0" encoding="utf-8"?>
<sometag>
<txt src="txt1.txt"/>
<txt src="img1.jpg"/>
</sometag>
<sometag>
<img src="txt2.txt"/>
<img src="img2.jpg"/>
</sometag>
This relies on the idea the child count and the parent count being
exactly the same. Theres a way to write so this isn't the case but if
we gave you all the answers you wouldnt have any fun :)
As such, have fun :)
On 9/28/05, Ragulf Pickaxe <ragulf(_dot_)pickaxe(_at_)gmail(_dot_)com>
wrote:
The real problem is that I don't want to have to know anything about
<sometag>. That is, I would be free to use (and nest!) whatever
non-proprietary tag inside my <repeat>, without modifing it.
Probably there's no way in XSLT 1.0 (if it is, why creating tunnel in
2.0 ;) , but if you see another solution...
Hi again Paolo,
Why can you not have a general template for the "Sometag" and other
elements that you just want to pass on?
I think that your own solution would be able to provide, if you change
the template that matches "Sometag" to the following:
<xsl:template match="*">
<xsl:param name="index" select="1"/>
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates>
<xsl:with-param name="index" select="$index"/>
</xsl:apply-templates>
<!-- sometag content -->
</xsl:copy>
</xsl:template>
The match="ax:items" is more specific than match="*" and thus has
higher priority.
My solution, I think, you would have to change three templates:
<xsl:template match="ax:repeat">
<xsl:apply-templates/> <!-- instead of <xsl:apply-templates
select="sometag"/>-->
</xsl:template>
<xsl:template match="*"> <!-- Instead of <xsl:template match="sometag" -->
<xsl:copy> <!-- Copy element (shallow copy) -->
<xsl:copy-of select="@*"/> <!-- Copy all attributes -->
<!-- other non-proprietary elements to be processed: -->
<xsl:apply-templates select="*[not(self::ax:items)]"/>
<!-- Propriotary elements to be processed: -->
<xsl:apply-templates select="ax:items[1]" mode="first"/>
</xsl:copy>
</xsl:template>
And remove the <sometag> and </sometag>from the
<xsl:template match="ax:items" mode="first">
..
</
Is this what you need?
Regards,
Ragulf Pickaxe :-)
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