xsl-list
[Top] [All Lists]

Re: Copy element but transform sub-element

2005-09-08 06:41:40
Hi,
Tempore 15:36:58, die 09/08/2005 AD, hinc in 
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com scripsit Maximilian Gärber 
<max(_at_)gaerber(_dot_)de>:

I need to only apply a template to the article element (and sub-elements)
the (rather complex) product element can be copied as is:

This looks like a proto-type scenario for an identity transform:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes"/>

<xsl:template match="node()|@*">
        <xsl:copy>
                <xsl:apply-templates select="node()|@*" />
        </xsl:copy>
</xsl:template>

<xsl:template match="article">
 <CHANGED_ARTICLE>
      <SOME_TABULAR-STYLED_XML/>
  </CHANGED_ARTICLE>
</xsl:template>

</xsl:stylesheet>


regards,
--
Joris Gillis (http://users.telenet.be/root-jg/me.html)
Deserta faciunt et innovationem appelant

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--



<Prev in Thread] Current Thread [Next in Thread>