Then inside the recreated line for each of the current group (which is
what at this point?)
current-group() return the sequence of items (that is things selcted by the
xsl:for-each-group select="l") that are um in the current group (which
in this case means a group of adjacent line with just the first one
having a 4th word.
position() positions the groups (rather than teh items as it would in a
xsl:for-each) so
<l n="{position()}">
does the right thing, then to get the content of the lines
<xsl:copy-of select="current-group()"/>
would actually give you back each of the l elements in the group, which
you don't want, you just want the contents of each of those lines so
<xsl:copy-of select="current-group()/node()"/>
would almost work but I wasn't sure if you needed to put a space at the
point that you joined the lines back so I did
<xsl:for-each select="current-group()">
<xsl:copy-of select="(node(),' ')"/>
</xsl:for-each>
which for each of the original lines copies all the children then adds a
space
that puts a space at the end as well so perhaps
<xsl:for-each select="current-group()[position()!=last()]">
<xsl:copy-of select="(node(),' ')"/>
</xsl:for-each>
<xsl:copy-of select="current-group()[position()=last()]/node()"/>
or something.
If you know that <lg n="44.6"><l n="3" and > <lg n="100.8"><l n="4">
really are short lines, then you can change things to
<xsl:for-each-group select="l" group-starting-with="
l[w[4]] |
lg[(_at_)n='44.6']/l[(_at_)n='3'] |
lg[(_at_)n='100.8']/l[(_at_)n='4']
">
David
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