This will fail because your input document is not wellformed XML: element
names must start with a letter.
When reporting that things fail, it's always a good idea to quote the error
message. You may not understand it, but it's likely that others will. And it
might be failing for some reason quite unrelated to the above. For example,
you might have failed to declare a variable called $number; or current()
might be the wrong node (you give no indication of the context of your XPath
expression).
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Ana Gaspar Martínez [mailto:annagaspar(_at_)gmail(_dot_)com]
Sent: 31 October 2005 08:47
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Acces nodes [help]
Well, i'm newest at xstl. I've a file like:
<list>
<word>
<word1>
<1>house</1>
<2>cat </2>
</word1>
</word>
<word>
<word2>
<1><little</1>
<2> bigger</2>
</word2>
</word>
</list>
And in a xml file i could find <find-list> word1</find-list>. The
number of the list(1,2,..) is save in a param of the xslt file.
In this example i had to obtain house or cat(it depends of the param
value). I try it with the follow sentence but it doesn't run:
document('../list.xml')//*[name()=current()/.]/*[name()=$number]/.
What's fail?
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail:
<mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--