Hmm I see. The only problem is there could be more tags like
WAAUXCallerID, which shouldn't be counted. So I only can rely on
WAAUXxx... (where xx can be any number)
However again repetitions aren't allowed.
e.g.
WAAUX01
WAAUX01
WAAUXWithholdNumberAllCalls
WAAUX04
WAAUXCallerID
Should output a 2. I am not sure if this problem is solvable at all.
Besides I have to stick with XSLT 1.0.
Regards
Houman
-----Original Message-----
From: Michael Kay [mailto:mike(_at_)saxonica(_dot_)com]
Sent: 05 October 2005 17:02
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Wildcard problem
In 2.0 you can use regular expressions. Here I think you just want
count(*[starts-with(name(),'WAAUX')]) -
count(*[starts-with(name(),'WAAUXCallerID')])
Michael Kay
http://www.saxonica.com/
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