I would suggest splitting the string into words using xsl:analyze-string and
then applying replace to each of the words.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: UlyLee [mailto:ulyleeka(_at_)yahoo(_dot_)com]
Sent: 21 November 2005 12:50
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] problem with replace()
Hi!
I have this tiny problem regarding replace() and
matches(). i have a search string like "traits dunion"
and a source string like "illtraits dunions", if i run
replace("illtraits dunions", "traits dunion", "rep1")
the result woul be "illrep1s".
But i want my replace function to replace strings when
the character before the search string is a space, a
valid punctuation or a start of the string while the
character that appears after the serach string is a
space or a valid character.
ex:
illtraits dunions ---> should not be replaced
ill traits dunions ---> should not be replaced
ill traits dunion s ---> ill rep1 s
ill "traits dunion" s ---> ill "rep1" s
ill (traits dunion) s ---> ill (rep1) s
ill"traits dunion"s ---> should not be replaced
what regular expression can i use of replace or
matchcs so that i can match this type of pattern?
thanks,
UlyLee
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