I've been around that block a few times, and I have found that the key
thing to remember is that XSL is XML. An XSL stylesheet is just another
XML document and can be treated the same as any other XML document by an
XSL transform.
As for copying the whole thing, an identity transform will do. If you use
the following stylesheet as all three arguments (in, xsl, and out) for an
XSLT processor, you'll get a copy of thing as output.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Jay Bryant
Bryant Communication Services
(presently consulting at Synergistic Solution Technologies)
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