How to process a list of files

Hi All,

I have input xml file as:

<Root>
<file fileloc="A/gen1.xml" />
<file fileloc="A/gen2.xml" />
</Root>

I have to transform this and get:

gen1.xml
gen2.xml


My XSL for the same is:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";>
        <xsl:output method="xml" version="1.0" encoding="UTF-8"
indent="yes"/>
        <xsl:template match="/">
<xsl:for-each select="Root/file">
                        <fileloc>
                                <xsl:attribute name="path"><xsl:value-of
select="concat(substring-before(substring-after(@fileloc,'/xml/'),'.'),'.htm
')"/> </xsl:attribute>
                                <xsl:attribute
name="noNamespaceSchemaLocation">MSD_book.xsd</xsl:attribute>
                                <xsl:text>&#13;</xsl:text>
                                <xsl:apply-templates select="script"/>
                                <xsl:apply-templates
select="document(@fileloc)/Test/topic"/>
                        </fileloc>
</xsl:for-each>
        </xsl:template>
        <xsl:template match="script">
                <scriptinc>
                        <xsl:copy-of select="@*"/>
                </scriptinc>
        </xsl:template>
        <xsl:template match="topic">
                <xsl:copy-of select="."/>
        </xsl:template>
</xsl:stylesheet>

With this xsl I am getting one xml file where i need two xml files as output
How to get output. How do get output when its done with first file
transform?

Thanks,
Shailesh
 



--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--