I fixed it :
<xsl:template name="escapeQuotes">
<xsl:param name="string"/>
<xsl:variable name="apos">'</xsl:variable>
<xsl:if test="not(contains($string,$apos))"><xsl:value-of
select="$string"/></xsl:if>
<xsl:if test="contains($string,$apos)"><xsl:value-of
select="substring-before($string,$apos)"/><xsl:value-of
select="$apos"/><xsl:value-of select="$apos"/><xsl:call-template
name="escapeQuotes"><xsl:with-param name="string"
select="substring-after($string,$apos)"/></xsl:call-template></xsl:if>
</xsl:template>
Philippe
-----Message d'origine-----
De : Philippe LAPLANCHE
Envoyé : lundi 12 décembre 2005 07:23
À : xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Objet : translate quote into quote quote
Hi,
I need to translate a string such as this one :
I'm sad that I can't do it by myself
Into :
I''m sad that I can''t do it by myself
I'm using XSLT 1.0, and I tried to do something like that :
<xsl:template name="escapeQuotes">
<xsl:param name="string"/>
<xsl:variable name="apos" select="'"/>
<xsl:if test="not(contains($string,$apos))"><xsl:value-of
select="$string"/></xsl:if>
<xsl:if test="contains($string,$apos)">
<xsl:value-of
select="substring-before($string,$apos)"/><xsl:value-of
select="$apos"/><xsl:value-of select="$apos"/><xsl:call-template
name="escapeQuotes"><xsl:with-param
name="substring-after($string,$apos)"/></xsl:call-template>
</xsl:if>
</xsl:template>
I'm doing something wrong ...
Philippe
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