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RE: translate quote into quote quote

2005-12-12 02:00:56
The only thing I can see that's obviously wrong is that

<xsl:with-param
name="substring-after($string,$apos)"/>

should be

<xsl:with-param name="string"
select="substring-after($string,$apos)"/> 

Michael Kay
http://www.saxonica.com/


-----Original Message-----
From: Philippe LAPLANCHE 
[mailto:philippe(_dot_)laplanche(_at_)horus-si(_dot_)com] 
Sent: 12 December 2005 06:23
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] translate quote into quote quote

Hi, 
I need to translate a string such as this one :
I'm sad that I can't do it by myself
Into :
I''m sad that I can''t do it by myself

I'm using XSLT 1.0, and I tried to do something like that :

<xsl:template name="escapeQuotes">
              <xsl:param name="string"/>
              <xsl:variable name="apos" select="'"/>
              <xsl:if
test="not(contains($string,$apos))"><xsl:value-of
select="$string"/></xsl:if>
              <xsl:if test="contains($string,$apos)">
                      <xsl:value-of
select="substring-before($string,$apos)"/><xsl:value-of
select="$apos"/><xsl:value-of select="$apos"/><xsl:call-template
name="escapeQuotes"><xsl:with-param
name="substring-after($string,$apos)"/></xsl:call-template>
              </xsl:if>
      </xsl:template>


I'm doing something wrong ... 

Philippe




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