On Thu, 1 Dec 2005 20:07:27 -0600
"Jay Bryant" <jay(_at_)bryantcs(_dot_)com> wrote:
Hi, Mike,
That's a question to which you can find an answer in Dave Pawson's FAQ at
http://www.dpawson.co.uk/xsl/sect2/N2696.html
In your case, something like the following will do the trick:
<xsl:template match="page[not(@tab=following::page/@tab)]">
<!-- Process the page nodes with unique values for the tab attribute
here -->
</xsl:template>
What I ended up doing is the following:
<xsl:for-each select="page">
<xsl:variable name="prev" select="preceding-sibling::page[position()=1]"/>
<xsl:if test="not($prev) or @tab!=$prev/@tab">
I'm not sure how this differs from your method but I found that a)
[position()=1] must be used to isolate only the immediate sibling and b)
the @tab!=$prev/@tab strangely returns false if $prev is nil.
Mike
You can do the same trick in the select attributes of apply-templates or
for-each instructions, too, depending on exactly what you need to do.
Jay Bryant
Bryant Communication Services
----- Original Message -----
From: "Michael B Allen" <mba2000(_at_)ioplex(_dot_)com>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Thursday, December 01, 2005 3:53 PM
Subject: [xsl] Exclude by Sibling Condition
Considering the following XML fragment:
<page name="p0" tab="products"/>
<page name="p1" tab="products"/>
<page name="p2" tab="products"/>
<page name="d" tab="downloads"/>
<page name="s" tab="support"/>
How can I select a subset that excludes elements with a tab attribute
value matching that of a previous sibling?
Meaning I want a list with no redundant @tab values like:
<page name="p0" tab="products"/>
<page name="d" tab="downloads"/>
<page name="s" tab="support"/>
Thanks,
Mike
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