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Re: Exclude by Sibling Condition

2005-12-01 19:07:27
Hi, Mike,

That's a question to which you can find an answer in Dave Pawson's FAQ at
http://www.dpawson.co.uk/xsl/sect2/N2696.html

In your case, something like the following will do the trick:

<xsl:template match="page[not(@tab=following::page/@tab)]">
  <!-- Process the page nodes with unique values for the tab attribute
here -->
</xsl:template>

You can do the same trick in the select attributes of apply-templates or
for-each instructions, too, depending on exactly what you need to do.

Jay Bryant
Bryant Communication Services


----- Original Message ----- 
From: "Michael B Allen" <mba2000(_at_)ioplex(_dot_)com>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Thursday, December 01, 2005 3:53 PM
Subject: [xsl] Exclude by Sibling Condition


Considering the following XML fragment:

  <page name="p0" tab="products"/>
  <page name="p1" tab="products"/>
  <page name="p2" tab="products"/>
  <page name="d" tab="downloads"/>
  <page name="s" tab="support"/>

How can I select a subset that excludes elements with a tab attribute
value matching that of a previous sibling?

Meaning I want a list with no redundant @tab values like:

  <page name="p0" tab="products"/>
  <page name="d" tab="downloads"/>
  <page name="s" tab="support"/>

Thanks,
Mike

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