xsl-list
[Top] [All Lists]

Re: Including <?xml ...> in the result tree

2006-01-30 02:49:35

taka a look at the xsl:output element.

Sebastian Tennant wrote:

Hi all,

I want to output an XHTML doc with the following prologue:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
   "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";>

However an xsl template including the following:

 <xsl:processing-instruction name="xml">
   version="1.0" encoding="UTF-8"
 </xsl:processing-instruction>
 <![CDATA[
   <?xml version="1.0" encoding="UTF-8"?>
   <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
                "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";>]]>

produces the following error in xalan:

 XSLT Error: A processing instruction name cannot be 'xml'

and the cdata section is output as &lt;!DOCTYPE... etc.

How best should this be achieved?

TIA

sdt


--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--




--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--



<Prev in Thread] Current Thread [Next in Thread>