Yes, the result is well-defined. A stylesheet that you include has higher
precedence than one that you import (directly or indirectly).
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: mazerunner(_at_)gmx(_dot_)de [mailto:mazerunner(_at_)gmx(_dot_)de]
Sent: 29 January 2006 01:02
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Mixing imports and includes - specified behaviour?
Hi there,
in this example I found different result from different XSLT
processors,
just call main.xsl with input '<one/>':
main.xsl :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; >
<xsl:include href="first.xsl"/>
<xsl:include href="second.xsl"/>
<xsl:template match="/">
<b>
<xsl:for-each select="one | two | three | four">
<xsl:apply-templates select="."/>
</xsl:for-each>
</b>
</xsl:template>
</xsl:stylesheet>
first.xsl :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; >
<xsl:template match="one">
<xsl:apply-imports/>
<xsl:text>1</xsl:text>
</xsl:template>
<xsl:template match="two">
<xsl:text>2</xsl:text>
</xsl:template>
</xsl:stylesheet>
second.xsl :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; >
<xsl:import href="third.xsl"/>
<xsl:template match="three">
<xsl:text>3</xsl:text>
</xsl:template>
<xsl:template match="four">
<xsl:text>4</xsl:text>
</xsl:template>
</xsl:stylesheet>
third.xsl :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; >
<xsl:template match="one">
<xsl:text>this is also one</xsl:text>
</xsl:template>
</xsl:stylesheet>
And this is how it works: In main.xsl I include two
stylesheets. In one
stylesheet I import a template that is activated in the other.
I have following question: Is the result defined in XSLT 1.0
and XSLT 2.0?
Thanks in advance
Tobias
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