Hi there,
in this example I found different result from different XSLT processors,
just call main.xsl with input '<one/>':
main.xsl :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:include href="first.xsl"/>
<xsl:include href="second.xsl"/>
<xsl:template match="/">
<b>
<xsl:for-each select="one | two | three | four">
<xsl:apply-templates select="."/>
</xsl:for-each>
</b>
</xsl:template>
</xsl:stylesheet>
first.xsl :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:template match="one">
<xsl:apply-imports/>
<xsl:text>1</xsl:text>
</xsl:template>
<xsl:template match="two">
<xsl:text>2</xsl:text>
</xsl:template>
</xsl:stylesheet>
second.xsl :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:import href="third.xsl"/>
<xsl:template match="three">
<xsl:text>3</xsl:text>
</xsl:template>
<xsl:template match="four">
<xsl:text>4</xsl:text>
</xsl:template>
</xsl:stylesheet>
third.xsl :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:template match="one">
<xsl:text>this is also one</xsl:text>
</xsl:template>
</xsl:stylesheet>
And this is how it works: In main.xsl I include two stylesheets. In one
stylesheet I import a template that is activated in the other.
I have following question: Is the result defined in XSLT 1.0 and XSLT 2.0?
Thanks in advance
Tobias
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--