Michael Kay wrote:
you can get the Nth item in a sequence using SEQ[N].
In the rare cases where that's inconvenient because
it changes the evaluation context, you can use
subsequence(SEQ, N, 1).
When can this happen? Can you show an example?
Regards,
--drkm
Suppose that you have a structure like this:
<e>
<itemref nr="5"/>
<itemref nr="7"/>
<itemref nr="10"/>
</e>
<f>
<item/>...
</f>
and you want to select the 5th, 7th, and 10th <item> elements.
You can't do
<xsl:for-each select="/e/itemref">
<xsl:value-of select="/f/item[(_at_)nr]"/>
because the context inside the predicate is wrong.
But you can do
<xsl:for-each select="/e/itemref">
<xsl:value-of select="subsequence(/f/item, @nr, 1)"/>
Of course there are other circumventions as well, involving variables or
current() - but it's nice to be aware of this alternative.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Florent Georges [mailto:darkman_spam(_at_)yahoo(_dot_)fr]
Sent: 13 January 2006 13:14
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Selecting the first item from a tokenized string
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