Sorry, I cut down my example so as to not overwhelm the reader --
Desired output:
<document>
<job>
<status>1/1-3</status>
</job>
<job>
<status>1/4-5</status>
</job>
<job>
<status>2/1-4</status>
</job>
<job>
<status>2/5</status>
</job>
-------- Original Message --------
Subject: RE: [xsl] Increment value by group
Date: Wed, 11 Jan 2006 16:44:20 -0000
From: Michael Kay <mike(_at_)saxonica(_dot_)com>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
You'll have to explain more clearly. I can't see any relationship between
the four jobs in your input and the five jobs in your output.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: watchstone(_at_)netzero(_dot_)com
[mailto:watchstone(_at_)netzero(_dot_)com]
Sent: 11 January 2006 16:18
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Increment value by group
Hello: I want to process nodes based on grouping by
<quantity>. The <increment> element is used as a running
"total" based on grouping. So basically, when <quantity> is
"1", I want to process all of them as a group and use the
<increment> value to produce an output like this:
1/1-3 (i.e. <increment> value is "3")
1/4-5 (i.e. <increment> value if "2" but starts with
preceding <increment value)
When <quantity> changes, I want the <increment> value to also
start over with "1".
Can I use <xsl:for-each-group> or some such element to
accomplish this.
<?xml version="1.0"?>
<document>
<job>
<quantity>1</quantity>
<increment>3</increment>
</job>
<job>
<quantity>1</quantity>
<increment>2</increment>
</job>
<job>
<quantity>2</quantity>
<increment>4</increment>
</job>
<job>
<quantity>2</quantity>
<increment>1</increment>
</job>
</document>
Desired output:
<document>
<job>
<status>1/1-3</status>
</job>
<job>
<status>1/4-5</status>
</job>
<job>
<status>1/6</status>
</job>
<job>
<status>2/1-4</status>
</job>
<job>
<status>2/5</status>
</job>
</document>
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