Hi,
(Using Saxon8B, XSLT 2.0)
Is the name of the input XML file and the XSLT file
available to the parser?
It should be possible to get the URI of the input document using
document-uri(/) - provided it is known (it won't be known if the input is
supplied as an anonymous StreamSource, for example).
The output file name isn't known, you could pass it by parameter as others
have suggested.
Michael Kay
http://www.saxonica.com/
If not, how can the
following be done?
For example:
If input is "in.xml" being processed by "xform.xsl", I want
the generated output to list the two
files as ...
:
//Input XML : in.xml
//Transformer : xform.xsl
:
:
Thanks,
Anupam.
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