On 1/4/06, Agnisys <agnisys(_at_)yahoo(_dot_)com> wrote:
Hi,
(Using Saxon8B, XSLT 2.0)
Is the name of the input XML file and the XSLT file available to the
parser? If not, how can the
following be done?
For example:
If input is "in.xml" being processed by "xform.xsl", I want the generated
output to list the two
files as ...
:
//Input XML : in.xml
//Transformer : xform.xsl
You can use the base-uri() function to return the uri of the tree
containing the context node, so to get the input filename use:
//Input XML :<xsl:value-of select="tokenize(base-uri(/), '/')[last()]"/>
To get the stylesheet filename you could use base-uri(document(''))
but do you really need to discover it... couldn't you just hard code
it in as you decide the name when you do file -> save :)
By the way, there was a change between Saxon 8.6 and 8.6.1 where
document-uri() became base-uri() (I think anyway, I had to make the
change, maybe Mike will confirm) so it's worth getting the very latest
version.
cheers
andrew
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