In XPath 1.0 there is no way of constructing a sequence of strings (there's
no such type in the data model), and there is no way of constructing new
nodes, so I'm afraid this is impossible.
In 2.0 it's straightforward:
for $x in (your current expression)
return substring-after($x, '(mm)')
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Dariusz Borowski [mailto:d(_dot_)borowski(_at_)web(_dot_)de]
Sent: 02 March 2006 00:59
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Expression in XPath
Hi!
Could anyone help me? I have this result:
========================================================
(mm)B-1: A eTSS Login
(mm)B-2: A eLogbook Viewer Login
(mm)B-3: A Rig Activity Entry (Req. # 6.2.2.1.1, 6.2.2.3.5, 3.5.1.1)
(mm)B-4: A Access tool from PC outside the firewall in SCTF
(mm)B-5: A eReport Login
(mm)B-6: A Privileged User ? Login
========================================================
from this expression:
//office:body/office:text/table:table/table:table-row/table:ta
ble-cell/text:p[starts-with(text(), '(mm)')]
But, I would like to get the following result with ONE Expression:
========================================================
B-1: A eTSS Login
B-2: A eLogbook Viewer Login
B-3: A Rig Activity Entry (Req. # 6.2.2.1.1, 6.2.2.3.5, 3.5.1.1)
B-4: A Access tool from PC outside the firewall in SCTF
B-5: A eReport Login
B-6: A Privileged User ? Login
========================================================
I tried already something like this:
//office:body/office:text/table:table/table:table-row/table:ta
ble-cell/text:p[substring(starts-with(text(), '(mm)'), 4)]
but it didn't work... :(
Thanks for any help!
Dariusz
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