If your source XML has extraneous new lines between elements, it may be
picking that up. If you give up what your select statement is, we could
probably have a better idea of what is wrong.
G. Ken Holman wrote:
At 2006-03-24 08:13 +0800, rostom aghanian wrote:
I have multiple xsl:for-each loops where I am trying to output the
position of
my index in each loop. These xsl:for-each loops are NOT nested. The
problem is
that the Position() function does not seem to reset itself once I am
done with
one loop and move on to the next. So if my first loop contained 5
items, I will
get 1 through 5 outputted, but then when I start my next loop the
Position()
outputs 6, 7, 8, etc. I need it to restart the counter. How would I
go about
doing this?
XPath defines the position() function as returning the current node's
position in the current context as calculated by the evaluation's
context.
This means that each time you do a select= it returns a current node
list and your position in that list *always* starts at 1.
According to your evidence, the processor is broken ... perhaps you
are misinterpreting what you have from what you are seeing.
I hope this helps.
. . . . . . . . Ken
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