name() should return the lexical QName of the attribute, that is
"fo:text-align". However, you don't want to be testing namespace prefixes,
because users are allowed to choose any prefix they like. The construct you
want is
<xsl:copy-of select="..../@fo:*"/>
No need for the for-each and the xsl:if.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: news(_at_)swisslab(_dot_)de [mailto:news(_at_)swisslab(_dot_)de]
Sent: 29 March 2006 15:39
To: 'xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com'
Subject: [xsl] XSL 1.1 -> Asking for an attribut namespace
Hello List,
I've a XML:
<?xml version="1.0" encoding="ISO-8859-1" standalone="yes" ?>
<Spalten xmlns:fo="http://www.w3.org/1999/XSL/Format";>
<Datenursprung>//SVERLAUF</Datenursprung>
<Spalte anzahl="1" breite-in-prozent="3" text-align="right">
<Titel fix="true"></Titel>
<Data fix="true" fo:text-align="right">position()</Data>
</Spalte>
</Spalten>
The problem I have comes when I try to copy all attributes of
the <Data/>
node into my result dataset. I want to copy each attribut as
long as it has
a namespace of "fo:".
<xsl:for-each select="$ListData/Spalten/Spalte[$i]/@*">
<xsl:if test="starts-with(name(), 'fo:')">
<xsl:copy-of select="."/>
</xsl:if>
</xsl:for-each>
name() always gives me back the correct name, but without the
namespace of
the attribut. I want to filter ther attributes this way since
I dont want to
have attributes like "anzahl" in my FO result dataset.
Doeas anybody hase a idea how I can solve my probem?
Thanks & with best regards, Jan
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