No, you cannot use * to refer to all the elements, you need to specify
them all as cdata-section-elements contains a list of qualified names as
its value. Note that in cdata-section-elements you specify the elements
in the *output* not in the *source* XML.
Best Regards,
George
---------------------------------------------------------------------
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com
Jagdishwar (Jagsmiles) wrote:
I would like to put the <![CDATA[ elements as is in my transformed xml.
So, i had used following declaration at the beginning of the xsl:
<xsl:output method="xml" cdata-section-elements="elementOne
elementTwo elementThree"/>
Its works fine for transforming the specified elements (i.e elementOne
elementTwo elementThree) along with the CDATA.
Actually i want to preserve CDATA as is, in all the elements my source xml.
But Its not very comfortable to add each and every element to the
cdata-section-elements attribute.
I tried using * instead of the element names.
<xsl:output method="xml" cdata-section-elements="*"/>
but it does not work, the xslt transformer says:
"This name may not contain the '*' character"
But * works fine in other elements like xsl:strip-space
<xsl:strip-space elements="*"/>
Is there any way, where i can specify in xsl, to preserve all the
CDATA for all the elements of the source xml document.
Thank you all
Kind Regards,
Jagdishwar,
Jagsmiles @ gmail.com
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