Sorry, can't be done. The XSLT processor doesn't get to see where the CDATA
sections were in the source document.
Remember that CDATA sections are just a keyboard shortcut. The following are
all exactly equivalent, and your XSLT processor will see the same input
whichever form you use:
<e>">"</e>
<e>">"</e>
<e><![CDATA[">"]]></e>
As a matter of interest, *why* do you want to preserve the CDATA sections in
the input document?
If it's really important, you could put the XML through a Perl program or
similar that converts the CDATA section to an XML element as a
pre-processing phase and then does the reverse as a post-process.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Jagdishwar (Jagsmiles) [mailto:jagsmiles(_at_)gmail(_dot_)com]
Sent: 14 May 2006 18:29
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Preserve CDATA for all elements
I would like to put the <![CDATA[ elements as is in my
transformed xml.
So, i had used following declaration at the beginning of the xsl:
<xsl:output method="xml" cdata-section-elements="elementOne
elementTwo elementThree"/>
Its works fine for transforming the specified elements (i.e
elementOne elementTwo elementThree) along with the CDATA.
Actually i want to preserve CDATA as is, in all the elements
my source xml.
But Its not very comfortable to add each and every element to
the cdata-section-elements attribute.
I tried using * instead of the element names.
<xsl:output method="xml" cdata-section-elements="*"/>
but it does not work, the xslt transformer says:
"This name may not contain the '*' character"
But * works fine in other elements like xsl:strip-space
<xsl:strip-space elements="*"/>
Is there any way, where i can specify in xsl, to preserve all
the CDATA for all the elements of the source xml document.
Thank you all
Kind Regards,
Jagdishwar,
Jagsmiles @ gmail.com
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