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[xsl] XSLT 2.0/XPath 2.0 Date arithmetic

2006-05-17 14:30:09
Given a parameter, let's call it "today" in the form of this string "20060517", 
how do I create a variable, let's call it "tMinus1" such that it represents a 
day earlier than "20060517", that would be "20060516". So long as "$today" 
isn't the first day of a month, a simple subtraction and followed by a type 
cast that I don't grasp would do the trick.

What I'm looking for is guidance on date arithmetic.

Thanks.

-- 
Charles Knell
cknell(_at_)onebox(_dot_)com - email

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