Dave Pawsons' FAQ covers date processing here for xslt2
http://www.dpawson.co.uk/xsl/rev2/dates.html.
Which version and processor are you using?
Karen
-----Original Message-----
From: cknell(_at_)onebox(_dot_)com [mailto:cknell(_at_)onebox(_dot_)com]
Sent: Wednesday, May 17, 2006 2:30 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] XSLT 2.0/XPath 2.0 Date arithmetic
Given a parameter, let's call it "today" in the form of this string
"20060517", how do I create a variable, let's call it "tMinus1" such
that it represents a day earlier than "20060517", that would be
"20060516". So long as "$today" isn't the first day of a month, a simple
subtraction and followed by a type cast that I don't grasp would do the
trick.
What I'm looking for is guidance on date arithmetic.
Thanks.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
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