David,
Below is the XSLT that I am currently trying to use. The portion
above the first comment creates the structure that I want except that
it doesn't include the <Root> element that the <Story> element is
contained in. Then when I add the instructions below the first
comment to try to rename the elements, I lose the structure and tags
that I want. My XML file structure is as such:
<Root>
<Story>
<articleTitle>Content</articleTitle>
<articleSubTitle>Content</articleSubTitle>
<author><authorFname>content</authorFname></author>
This is my stylesheet:
<xsl:template match="Story">
<xsl:copy>
<BB><TG>
<xsl:apply-templates select="articleTitle|articleSubTitle"/>
</TG></BB>
<xsl:apply-templates select="*[not(self::articleTitle or
self::articleSubTitle)]"/>
</xsl:copy>
</xsl:template>
<!--Above this line creates the directory structure that I need-->
<xsl:template match="Root">
<DG>
<xsl:apply-templates select="@*|node()"/>
</DG>
</xsl:template>
<xsl:template match="Story">
<D>
<xsl:apply-templates select="@*|node()"/>
</D>
</xsl:template>
<chad/>
Chad Chelius
AGI Training
cchelius(_at_)agitraining(_dot_)com
On Jun 1, 2006, at 12:05 PM, David Carlisle wrote:
I need all of the other elements to come over as
well and I need to rename those elements.
yes that's what the
<xsl:apply-templates select="*[not(self::title or self::subtitle)]"/>
is doing, applying your templates to all the child elements.
Sounds like you don't want document to go to document though so change
<xsl:copy> to <D>
and when I said
you just need a standard identity template,
read that as "you just need the templates doing whatever
transformation
they are doing"
David
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