In XSLT 2.0, use the xsl:namespace instruction.
In 1.0, there's a workaround:
<xsl:variable name="dummy">
<xsl:element name="{$prefix}:{$local}" namespace="{$uri}"/>
</xsl:variable>
<xsl:copy-of select="xx:node-set($dummy)//namespace::*"/>
That is, create an element in the relevant namespace, then copy its
namespace nodes.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Jim Earley [mailto:Jim(_dot_)Earley(_at_)flatironssolutions(_dot_)com]
Sent: 06 June 2006 00:38
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Generating an XSLT stylesheet with additional
namespaces
Hello,
I'm trying to generate a "stub" XSL stylesheet by reading an
XML Schema file to generate the template matches for all
declared elements. The problem I have is that the schema is
using a default namespace and I want to declare a namespace
prefix (and the URI) in the generated stylesheet.
For example:
<xsl:template match="/">
<xsl:element name="xsl:stylesheet">
<xsl:if test="@targetNamespace">
<!--
specify the namespace on the
stylesheet element???
-->
</xsl:if>
<xsl:for-each select="//xsd:element[(_at_)name]">
<xsl:sort select="@name"/>
<xsl:apply-templates select="."/>
</xsl:for-each>
</xsl:element>
</xsl:template>
How can I specify an "additional" and URI on the root
xsl:stylesheet element?
Any ideas?
Thanks in advance for your help.
================
Jim Earley
XML Developer/Consultant
Flatirons Solutions
4747 Table Mesa Drive
Boulder, CO 80301
jim(_dot_)earley(_at_)flatironssolutions(_dot_)com
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