Thanks for your reply Michael and to all others as well. I'm still
having trouble with this issue, so I decided to include the files
that I'm working with (content has been changed to protect the
innocent). As you will probably notice by looking at my XSLT, I am a
definite newbie. So if anyone has any recommendations or looks at it
and says "Whoa, you are way off base here!" I can take it, please
offer your advice. Basically, I am having difficulties with the
<author> section of the xslt. It is currently doing what I want,
however I need <author> to show up as <Author>. Seems very basic, but
I am having great difficulties accomplishing this in my xslt. So here
are the files below, thanks in advance for everyones help.
My XML file:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Root>
<Story>
<articleTitle>Title </articleTitle>
<articleSubTitle>Subtitle </articleSubTitle>
<author><authorFname>Jane</authorFname>
<authorLname>Doe</authorLname>, <authorDegree>RN, MPS</
authorDegree>
</author>
<author><authorFname>John</authorFname>
<authorLname>Doe</authorLname>, <authorDegree>MD</
authorDegree>
</author>
<abstract_body>
<italic>Miscellaneous Text Goes Here </italic>
</abstract_body>
<subHead>Subhead </subHead>
<body_text>Body Text goes here: </body_text>
<body_text>Body Text. </body_text>
</Story>
<Source><PublisherName>Publishing Inc</
PublisherName><Publication>My Very Special Journal </
Publication><Issn>1234-5678 </Issn><Date>
<Month>July</Month>
<Year>2006</Year>
</Date>Volume <Volume>12</Volume>
<Issue>Issue <IssuePart>8</IssuePart>
</Issue>Pages <Pages>9ndash;22 </Pages><FirstPage>97</
FirstPage><Pages
> </Pages><LastPage>109</LastPage><Pages> </Pages></Source>
<department>Department: My Department</department>
</Root>
My XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<!-- Set the destination document to XML format and apply
indenting to make it easier to read -->
<xsl:output method="xml" indent="yes"/>
<xsl:template match="Root">
<ArticleSet>
<Article>
<Journal>
<PublisherName>
<xsl:apply-templates select="Source/
PublisherName"/>
</PublisherName>
<JournalTitle>
<xsl:apply-templates select="Source/
Publication"/>
</JournalTitle>
<Issn>
<xsl:apply-templates select="Source/Issn"/>
</Issn>
<Volume>
<xsl:apply-templates select="Source/Volume"/>
</Volume>
<Issue>
<xsl:apply-templates select="Source/Issue"/>
</Issue>
<PubDate>
<Year>
<xsl:apply-templates select="Source/Date/
Year"/>
</Year>
<Month>
<xsl:apply-templates select="Source/Date/
Month"/>
</Month>
</PubDate>
</Journal>
<ArticleTitle>
<xsl:apply-templates select="Story/articleTitle"/
>. <xsl:apply-templates
select="Story/articleSubTitle"/>
</ArticleTitle>
<FirstPage>
<xsl:apply-templates select="Source/FirstPage"/>
</FirstPage>
<LastPage>
<xsl:apply-templates select="Source/LastPage"/>
</LastPage>
<!-- This is the section were I want <author> to be <Author> -->
<AuthorList>
<!-- <Author>-->
<xsl:copy-of select="Story/author"/>- <!-- </
Author> -->
</AuthorList>
<Abstract>
<xsl:apply-templates select="Story/abstract_body"/>
</Abstract>
</Article>
</ArticleSet>
</xsl:template>
</xsl:stylesheet>
On Jun 13, 2006, at 4:03 PM, Michael Kay wrote:
You can't do it using xsl:copy-of. Instead you walk the tree using
xsl:apply-templates, changing the name of each node as you go. If
there are
nodes you don't want to change, you can handle them with an identity
template:
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
and then you just write additional rules for the nodes you do want to
change.
Michael Kay
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