Very interesting. Do you think this will work with XSL 1.0?
My parser (MSXML) doesn' support 2.0, but I do have FXSL.
-Steve
On 7/12/06, Dimitre Novatchev <dnovatchev(_at_)gmail(_dot_)com> wrote:
Here's one possible solution:
This transformation:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:f="http://fxsl.sf.net/";
exclude-result-prefixes="f xs"
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