On 7/17/06, andrew welch <andrew(_dot_)j(_dot_)welch(_at_)gmail(_dot_)com>
wrote:
The problem here, Mukul, is that for each leaf node in the source
document, all leaf nodes in $doc2 will be copied. If you were to add
a few extra leaf nodes to the examples this would become apparent.
Thanks Andrew, for pointing this to me..
I believe, the following should work:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes" />
<xsl:variable name="doc2" select="document('file2.xml')" />
<xsl:template match="node() | @*">
<xsl:copy>
<xsl:apply-templates select="node() | @*" />
</xsl:copy>
</xsl:template>
<xsl:template match="*[* and not(*/*)]">
<xsl:copy>
<xsl:copy-of select="*" />
<xsl:copy-of select="$doc2//*[not(*)]" />
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(*)]" />
</xsl:stylesheet>
Regards,
Mukul
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