At 2006-07-18 17:24 -0400, Steve wrote:
Well after success with my first recursive template I was all set to
make one of my own, but now shamefully am coming to the list for
advice over something that appears quite simple.
XML ------->
...
Desired output ------->
<!-- @count corresponds to number of times
the preference appeared among the list of <people> --->
..
Stipulation: --------->
<out>'s must be sorted alphabetically, regardless of <option> order.
I'm not sure why you are using recursion ... I
hope the following helps. BTW, I think your
desired output count was wrong for the third item.
. . . . . . . . . Ken
T:\ftemp>type steve.xml
<?xml version="1.0" encoding="US-ASCII"?>
<data>
<options>
<o type="A">who</o>
<o type="A">what</o>
<o type="A">when</o>
<o type="B">how</o>
<o type="B">nexus</o>
<o type="B">triumph</o>
<o type="C">alligator</o>
<o type="C">spurn</o>
</options>
<people>
<person pref="who" />
<person pref="nexus" />
<person pref="how" />
<person pref="alligator" />
<person pref="spurn" />
<person pref="triumph" />
.... etc ....
</people>
</data>
T:\ftemp>type steve.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:steve="urn:x-steve"
version="1.0">
<xsl:output indent="yes"/>
<xsl:template match="/data">
<xsl:variable name="people" select="people/person"/>
<xsl:variable name="options" select="options/o"/>
<output>
<xsl:for-each select="$options">
<xsl:sort select="@type"/>
<xsl:if test="generate-id(.)=
generate-id($options[(_at_)type=current()/@type][1])">
<out type="{(_at_)type}"
count="{count($people[(_at_)pref=$options[@type=current()/@type]])}"/>
</xsl:if>
</xsl:for-each>
</output>
</xsl:template>
</xsl:stylesheet>
T:\ftemp>xslt steve.xml steve.xsl con
<?xml version="1.0" encoding="utf-8"?>
<output xmlns:steve="urn:x-steve">
<out type="A" count="1"/>
<out type="B" count="3"/>
<out type="C" count="2"/>
</output>
T:\ftemp>
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