I, too had trouble understanding the requirement, but what caught my attention
was the use of xsl:for-each. It looks (at first glance) like another mis-use of
xsl:for-each where the correct approach would be to define two templates:
<xsl:template match="section[not(subsection)]">
...
</xsl:template>
and
<xsl:template match="section[subsection]">
...
</xsl:template>
Then simply apply-templates.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk>
Sent: Mon, 24 Jul 2006 15:33:05 +0100
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] listing elements & sub-elements in a seqence - skiping
elemts if sub-elemts are present
1) Whether the above code is correct or not, pls can forward me the
syntax code equivalent to <for-each - //section[with no subsection] |
//section/subsection..>
I didn't follow the rest of your problem statement, but if you put in
the obvious missing syntax bits like ="..." then essentially what you
write is legal Xpath to select the elements that you want.
<xsl:for-each select="//section[not(subsection]|//section/subsection"
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