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[xsl] populating table with sorted elements

2006-07-29 07:43:27
I am a newcomer to XML/XSLT and am struggling
with a bit of code in which I am attempting to populate
a six-column table, while allowing an xsl:sort.

Here is a section of my current code:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

...

<table width="970" border="0" cellspacing="0" cellpadding="0">
   <xsl:for-each select="xml/work/*[position() mod 6 = 1]">
       <tr>
           <xsl:apply-templates
select=".|following-sibling::*[position() &lt; 6]" />
       </tr>
   </xsl:for-each>
</table>

...

The XML structure I've set up looks like this:

<xml>
   <work>
       <piece>
       </piece>
        <piece>
       </piece>
       ...
   </work>
</xml>

How would I go about adding sort functionality? It seems like it would
be easy enough, yet all of my attempts so far have failed...

Any suggestions would be much appreciated!


Christian

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