I think this requires two passes: first sorting, then grouping. So it should
be no problem if you are using XSLT 2.0, or XSLT 1.0 with the node-set()
extension. With plain XSLT 1.0 it may be difficult to achieve in a single
pass.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Christian Marc Schmidt [mailto:christianmarc(_at_)gmail(_dot_)com]
Sent: 29 July 2006 15:43
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] populating table with sorted elements
I am a newcomer to XML/XSLT and am struggling with a bit of
code in which I am attempting to populate a six-column table,
while allowing an xsl:sort.
Here is a section of my current code:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
...
<table width="970" border="0" cellspacing="0" cellpadding="0">
<xsl:for-each select="xml/work/*[position() mod 6 = 1]">
<tr>
<xsl:apply-templates
select=".|following-sibling::*[position() < 6]" />
</tr>
</xsl:for-each>
</table>
...
The XML structure I've set up looks like this:
<xml>
<work>
<piece>
</piece>
<piece>
</piece>
...
</work>
</xml>
How would I go about adding sort functionality? It seems like
it would be easy enough, yet all of my attempts so far have failed...
Any suggestions would be much appreciated!
Christian
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