colin
you saved my day. that works! with a small change
document(concat(document-uri(/),'/../','nextfile.xml'))
'/../' instead of '../' and a little bit wondering why there is no
function available in xslt to get the current xml file name. thanks
also to abel for his contribution... no i can't use parameters in
this case, i forgot to mention.
frank
Am 08.08.2006 um 08:42 schrieb Colin Adams:
I would think something like:
document (concat(document-uri(/),'../','nextfile.xml')) should do
the trick.
If you are using XSLT 2.0, you can use the resolve-uri function
which will be a bit neater.
From: Frank Marent <frank(_dot_)marent(_at_)emnemics(_dot_)ch>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] get the current xml file name
Date: Tue, 8 Aug 2006 08:18:37 +0200
hi
this is my first (xslt-beginner) question to this list, hoping my
question is not been answered 1 mio times. i was searching in the
archive to avoid this. :-)
i'm looking for a function that helps me to read and process
several .xml files by document(). the problem is that when i say
document('nextfile.xml')
the document() function tries to read the xml file in the path of
the current xslt (!) file. and that's not working for me. so i
want to redirect the document() function to the path of the
directory of the current .xml file.
how can i do that?
document-uri(/)
reports the whole (!) uri of the current xml file. that includes
the path i'm looking for, like
file:/C:/somewhere/anywhere/whereami/myfile.xml
and that's fine. but how can i now cut off 'myfile.xml' when
'myfile.xml' is always changing and i have no idea of this
filename in the xslt and replace it with 'nexfile.xml'?
i thought to find a function to
get the current xml file name
to be able to extract that file from the uri-path-string. but i
could not find anything about this. also trying to find a
function to find the last '/' in a string and extracting from
that with substring-after (). uahh.
i hope to find help here. any hint is very appreciated!
from switzerland
frank
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