Thanks,
98% of my problem was solved by your suggestion. Actually, the full senerio
required some additional statements.
I put in a <xsl:if> test to determine whether the optional element
<sortedItem> was present or not present (this solved my first set of
problems), and if it was, I used an <xsl:choose> for <xsl:when> <sortedItem>
contained only digits (this solved my second set of problems) and
<xsl:otherwise> when it contained digits together with addition characters,
as in
<sortedItem>05 (supl.)</sortedItem>
Without the <xsl:otherwise>, a NaN was returned. Thus my third set of
problems, yet unsolved.
If <xsl:value-of select="number(.)" /> renders properly when only digits
are present, what would the code look like to render
<sortedItem> 05 (supl.)</sortedItem>
as
<renderedItem> 5 (supl.)</renderedItem>
That is, removing the leading zero in this case.
The actual additional text in <sortedItem> may vary, but the digits always
come first and there is always a space after them. The text is usually,but
may not always be, (supl.).
Again, thanks for the first bit of help.
Mark
----- Original Message -----
From: "David Carlisle" <davidc(_at_)nag(_dot_)co(_dot_)uk>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Monday, August 21, 2006 7:56 AM
Subject: Re: [xsl] Eliminating leading zeros
number(.)
David
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