Let me clarify a little. I already have my set of programs in a
variable... call it $hitSet. So that's cool. And the bit from the sort
on down I'd already worked out. Good and good.
I need to get away from any looping based on program IDs. That's my
problem: program IDs are more fine-grained than my search item terms.
So I need to expand up, collecting up all the <schedule>s which have
the program IDs from $hitSet (and so representing each search item
discovery individually)
In pseudocode, my vision is something like
for each member of schedule ( a long list)
if this member's @program is found among the @ids in (hitSet list)
push (this member into Keepers list)
But I have no idea if that's possible in XSLT. I have a hunch it is,
and I'm just overlooking a very simple XPath function for the
assignment...
Bob P
simply(_dot_)bobp(_at_)gmail(_dot_)com
On 9/8/06, Steve <subsume(_at_)gmail(_dot_)com> wrote:
On 9/8/06, Bob Portnell <simply(_dot_)bobp(_at_)gmail(_dot_)com> wrote:
> for each search item
> find the set of programs which have that item
> convert this to the set of schedule items which have those programs
> for each in the schedule set
> sort by time
> report the show information.
<xsl:for-each $progSet/items[(_at_)item=@search]/@prog>
<xsl:variable name="prog" select="@prog" />
<xsl:for-each $scheduleSet[(_at_)prog = $prog]/@prog>
<xsl:sort select="@time" />
<xsl:value-of select="@showInfo"
</xsl:for-each>
</xsl:for-each>
> Given a variable $progSet which has a bunch of <programs> in it, how
> do I define a $schedSet which has only <schedule> items containing
> @program ids from $progSet?
>
> I've gotten as far as
> <xsl:variable name="schedSet" select="//schedule[(_at_)program . . {sound
> of screeching brakes}? />
Pretty sure I touched on this above. Let me know.
> Please excuse where I've strayed from proper XSLT vocabulary; I hope
> my intent is clear enough despite such lapses of inexperience.
No problemo. Was very well conveyed. =).
-S
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