Hi,
Your expression "//book[(bookshelf =
$bookshelfVar)]/author[not(.=preceding::author)]" is too strict (the
predicate too tolerant). You need to limit the preceding::author part to
match only authors that are on the same bookshelf. Similar thing for the
publisher. :-)
Besides, I would recommend trying to use keys and grouping techniques
like the Muenchian method. Something like:
(at top-level)
<xsl:key name="bookshelfs" match="bookshelf" use="." />
<xsl:key name="authors" match="author" use="concat(../bookshelf, '-',
.)" />
(inside bookshelf template)
<xsl:for-each select="key('bookshelfs', .)[1]">
...
</xsl:for-each>
(inside author template)
<xsl:for-each select="key('authors', concat(../bookshelf, '-', .)[1]">
...
</xsl:for-each>
Probably a lot quicker if your data file becomes larger. Using // is
usually very expensive in that case..
Kind regards,
Geert
Drs. G.P.H. Josten
Consultant
Daidalos BV
Source of Innovation
Hoekeindsehof 1-4
2665 JZ Bleiswijk
Tel.: +31 (0) 10 850 1200
Fax: +31 (0) 10 850 1199
www.daidalos.nl
KvK 27164984
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Van: Glen Mazza [mailto:grm7790(_at_)verizon(_dot_)net]
Verzonden: woensdag 4 oktober 2006 20:08
Aan: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Onderwerp: [xsl] Showing unique rows at multiple levels
Hello, for this input XML:
<books>
<book>
<title>T1</title>
<author>A5</author>
<publisher>P7</publisher>
<bookshelf>B4</bookshelf>
</book>
<book>
<title>T2</title>
<author>A6</author>
<publisher>P8</publisher>
<bookshelf>B4</bookshelf>
</book>
<book>
<title>T4</title>
<author>A5</author>
<publisher>P7</publisher>
<bookshelf>B6</bookshelf>
</book>
<book>
<title>T3</title>
<author>A5</author>
<publisher>P7</publisher>
<bookshelf>B4</bookshelf>
</book>
</books>
I would like an alphabetically sorted list of each unique
bookshelf, and under each bookshelf, each unique author of at
least one book on that shelf, and under each author, each
unique publisher of at least one book by that author (on that shelf).
I.e., for the above, the following is desired:
B4
--A5 (show just once even though 2 books of A5)
----P7 (show just once even though 2 books of P7 under A5 on B4)
--A6
----P8
B6
--A5
----P7
Unfortunately, I am getting this:
B4
--A5
----P7
--A6
----P8
B6
where A5 and P7 are erroneously missing under shelf B6, because A5 and
P7 already happen to exist under shelf B4. (In my sample
data, if I rename A5 to say A15 and P7 to P17, i.e., nodes
that don't exist elsewhere, these nodes then *will* appear under B6.)
Something is wrong with my filtering--I only want an author
to be suppressed if it is already listed for the *same*
shelf, and likewise with publishers under the same author
(under the same shelf).
Here is my XSLT:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="books">
<xsl:for-each select="//bookshelf[not(.=preceding::bookshelf)]">
<xsl:sort select="."/>
<xsl:apply-templates select='.'/>
</xsl:for-each>
</xsl:template>
<xsl:template match="bookshelf">
<xsl:variable name="bookshelfVar" select="."/>
<xsl:variable name="authorVar" select="../author"/>
<xsl:value-of select="."/>
<xsl:for-each select="//book[(bookshelf =
$bookshelfVar)]/author[not(.=preceding::author)]">
<xsl:sort select="."/>
<xsl:apply-templates select='.'/>
</xsl:for-each>
</xsl:template>
<xsl:template match="author">
<xsl:variable name="bookshelfVar" select="../bookshelf"/>
<xsl:variable name="authorVar" select="."/>
--<xsl:value-of select="."/>
<xsl:for-each select="//book[(bookshelf = $bookshelfVar)
and (author = $authorVar)]/publisher[not(.=preceding::publisher)]">
<xsl:sort select="."/>
<xsl:apply-templates select='.'/>
</xsl:for-each>
</xsl:template>
<xsl:template match="publisher">
----<xsl:value-of select="."/>
</xsl:template>
</xsl:stylesheet>
Can anyone see what I am doing wrong? Any help would be appreciated.
Thanks,
Glen
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