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RE: [xsl] Showing unique rows at multiple levels

2006-10-05 00:11:22
Actually, I meant something like:

<xsl:stylesheet version="1.0"
       xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:key name="bookshelves" match="bookshelf" use="." />
<xsl:key name="authors"     match="author"    use="concat(../bookshelf,
'-', .)" />
<xsl:key name="publishers"  match="publisher" use="concat(../bookshelf,
'-', ../author, '-', .)" />

<xsl:template match="books">
    <xsl:apply-templates select="book/bookshelf">
         <xsl:sort select="."/>
    </xsl:apply-templates>
</xsl:template>

<xsl:template match="bookshelf">
    <xsl:if test="generate-id(.) = generate-id(key('bookshelves',
.)[1])">
        <xsl:variable name="bookshelfVar" select="."/>
        <xsl:variable name="authorVar" select="../author"/>
        
        <xsl:text>&#10;</xsl:text>
        <xsl:value-of select="."/>
        
        <xsl:apply-templates select="/books/book[(bookshelf =
$bookshelfVar)]/author">
            <xsl:sort select="."/>
        </xsl:apply-templates>
    </xsl:if>
</xsl:template>

<xsl:template match="author">
    <xsl:if test="generate-id(.) = generate-id(key('authors',
concat(../bookshelf, '-', .))[1])">
        <xsl:variable name="bookshelfVar" select="../bookshelf"/>
        <xsl:variable name="authorVar" select="."/>

        <xsl:text>&#10;--</xsl:text>
        <xsl:value-of select="."/>

        <xsl:apply-templates select="/books/book[(bookshelf =
$bookshelfVar) and (author = $authorVar)]/publisher">
            <xsl:sort select="."/>
        </xsl:apply-templates>
    </xsl:if>
</xsl:template>

<xsl:template match="publisher">
    <xsl:if test="generate-id(.) = generate-id(key('publishers',
concat(../bookshelf, '-', ../author, '-', .))[1])">
        <xsl:text>&#10;----</xsl:text>
        <xsl:value-of select="."/>
    </xsl:if>
</xsl:template>

</xsl:stylesheet> 

It replaces // by explicit paths and preceding axis by keyed indexes..

Kind regards,
Geert


   
 
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Van: Geert Josten [mailto:geert(_dot_)josten(_at_)daidalos(_dot_)nl] 
Verzonden: donderdag 5 oktober 2006 8:13
Aan: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Onderwerp: RE: [xsl] Showing unique rows at multiple levels

Hi,

Your expression "//book[(bookshelf =
$bookshelfVar)]/author[not(.=preceding::author)]" is too 
strict (the predicate too tolerant). You need to limit the 
preceding::author part to match only authors that are on the 
same bookshelf. Similar thing for the publisher. :-)

Besides, I would recommend trying to use keys and grouping 
techniques like the Muenchian method. Something like:

(at top-level)

<xsl:key name="bookshelfs" match="bookshelf" use="." /> 
<xsl:key name="authors" match="author" 
use="concat(../bookshelf, '-', .)" />

(inside bookshelf template)

<xsl:for-each select="key('bookshelfs', .)[1]">
  ...
</xsl:for-each>

(inside author template)

<xsl:for-each select="key('authors', concat(../bookshelf, '-', .)[1]">
  ...
</xsl:for-each>

Probably a lot quicker if your data file becomes larger. 
Using // is usually very expensive in that case..

Kind regards,
Geert

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