On 10/17/06, Richard Lewis <richardlewis(_at_)fastmail(_dot_)co(_dot_)uk> wrote:
On Tuesday 17 October 2006 17:36, Sam Carleton wrote:
>
> <xsl:attribute name="revision">
> <xsl:if test="not(string(@revision)) = false()">
> <xsl:value-of select="@revision"/>
> </xsl:if>
> <xsl:if test="not(string(@revision))">
> <xsl:text>0</xsl:text>
> </xsl:if>
> </xsl:attribute>
>
What about:
<xsl:attribute name="revision">
<xsl:if test="@revision != ''">
<xsl:value-of select="@revision"/>
</xsl:if>
<xsl:if test="not(@revision)">
<xsl:text>0</xsl:text>
</xsl:if>
</xsl:attribute>
Richard,
I tried it, it did not work either.
On 10/17/06, David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk> wrote:
you are making it too hard:-)
test="@revision" is the test you arre looking for, but you don't need
the test at all.
replace
<node>
<xsl:attribute name="revision">
<xsl:if test="not(string(@revision)) = false()">
<xsl:value-of select="@revision"/>
</xsl:if>
<xsl:if test="not(string(@revision))">
<xsl:text>0</xsl:text>
</xsl:if>
</xsl:attribute>
</node>
by
<node revision="0">
<xsl:copy-of select="@revision"/>
</node>
Ok, I don't fully understand how the replacement code works,
considering there is no test in it. Here is the actual complete
template, using Richard's code. There is a comment about
<xsl:template match="Method|Cal|Blank">
<xsl:element name="{name()}">
<xsl:attribute name="objectID"><xsl:value-of
select="@objectID"/></xsl:attribute>
<xsl:attribute name="version"><xsl:value-of
select="@version"/></xsl:attribute>
<xsl:attribute name="revision">
<xsl:if test="@revision != ''">
<xsl:value-of select="@revision"/>
</xsl:if>
<xsl:if test="not(@revision)">
<xsl:text>0</xsl:text>
</xsl:if>
</xsl:attribute>
<!-- the line below isn't the best either. I simply need to copy over
all the children nodes, is there a better way? -->
<xsl:apply-templates mode="copyNode"/>
</xsl:element>
</xsl:template>
<xsl:template match="*" mode="copyNode">
<xsl:copy-of select="."/>
</xsl:template>
Sam
--
Miltonstreet Photography
http://www.miltonstreet.com
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