Re: [xsl] Determining if an optional attribute is present

<xsl:template match="Method|Cal|Blank">
  <xsl:element name="{name()}">
    <xsl:attribute name="objectID"><xsl:value-of
select="@objectID"/></xsl:attribute>
    <xsl:attribute name="version"><xsl:value-of
select="@version"/></xsl:attribute>
    <xsl:attribute name="revision">
      <xsl:if test="@revision != ''">
        <xsl:value-of select="@revision"/>
      </xsl:if>
      <xsl:if test="not(@revision)">
        <xsl:text>0</xsl:text>
      </xsl:if>
    </xsl:attribute>
<!-- the line below isn't the best either.  I simply need to copy over
all the children nodes, is there a better way? -->
    <xsl:apply-templates mode="copyNode"/>
  </xsl:element>
</xsl:template>

I'd do


<xsl:template match="Method|Cal|Blank">
  <xsl:copy>
 <xsl:attribute name="revision">0</xsl:attribute>
  <xsl:copy-of select="@objectID|@version|@revision|node()"/>
  </xsl:copy>
</xsl:template>

David

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